Answer:
(4+8)(4) = (x) 3
Step-by-step explanation:
The picture shows two secants intersecting at a point outside the circle. A beautiful pattern for this is: along each secant, the product (multiply) the <em>entire</em> secant by the <em>outside</em> part is the same.
(entire secant)(outside part) = (entire secant)(ouside part)
(4+8)(4) = (x)(3)
Answer:
Average rate of change is <u>0.80.</u>
Step-by-step explanation:
Given:
The two points given are (5, 6) and (15, 14).
Average rate of change is the ratio of the overall change in 'y' and overall change in 'x'. If the overall change in 'y' is positive with 'x', then average rate of change is also positive and vice-versa.
The average rate of change for two points
is given as:

Plug in
and solve for 'R'. This gives,

Therefore, the average rate of change for the points (5, 6) and (15, 14) is 0.80.
Answer: 4 hours and 35 minutes
Step-by-step explanation:
Answer: 0.8926
Step-by-step explanation:
Given : A shipment of 50 inexpensive digital watches, including 10 that are defective.
The probability that a digital watch is defective 
Sample size : n=10
Also, they reject the whole shipment if 1 or more in the sample are found defective.
Using the binomial probability formula :

Let x be the random variable that represents the number of defective watches.
The probability that the shipment will be rejected :-

Hence, the probability that the shipment will be rejected = 0.8926