Question

Plz i need help asap

Answer 1

1. x = 4

2. x = 3

3. x = 2 and x = -3

Step-by-step explanation:

solution 1

$\sqrt{3x+4}$ = 4

or, 3x+4 = 16 ( by squaring both sides)

or, 3x = 16 - 4

or, 3x = 12

or, x = 12/3

=4

solution 2

(x+5)^(2/3) = 4

or, (x+5) = 4^(3/2) ( by the rule of index)

or, x+5 = 2^3

or, x + 5 = 8

or, x = 8 - 5 = 3

solution 3

$\sqrt{x+7}$ - x = 1

or, $\sqrt{x+7}$ = x+1

or, x + 7 = (x+1)^2 (squaring both sides)

or, x + 7 = $x^{2}$ + 2x +1

or, $x^{2}$ + x - 6 = 0

or, $x^{2}$ + 3x - 2x - 6 = 0 ( by middle term factor method)

or, (x+3) (x -2) = 0

or, x= -3 and x = 2