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2 years ago

Help Please. Can't seem to understand how to do this. I have tried and watch over 5 videos. Can't seem to get it.

Mathematics

1 answer:

Snezhnost [94]2 years ago

7 0

Answer:

The solutions are the following:

z=2(cos(π6)+isin(π6))=√3+12i

z=2(cos(2π3)+isin(2π3))=−1+i√3

z=2(cos(7π6)+isin(7π6))=−√3−12i

z=2(cos(5π3)+isin(5π3))=1−i√3

<em>hope this helps!! :) --Siveth</em>

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$\mathbf{(x,y) = (-60,0)\ (60,0)}$

The center of the hyperbola is

$\mathbf{(h,k) = (0,0)}$

The distance from the center to the focal points is given as:

$\mathbf{c = 60}$

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$\mathbf{c^2 = 3600}$

The distance from the receiver to the transmitters is given as:

$\mathbf{2a = 100}$

Divide both sides by 2

$\mathbf{a = 50}$

Square both sides

$\mathbf{a^2 = 2500}$

We have:

$\mathbf{b^2 = c^2 - a^2}$

This gives

$\mathbf{b^2 = 3600 - 2500}$

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$\mathbf{\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1}$

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$\mathbf{\frac{(x - 0)^2}{2500} + \frac{(y - 0)^2}{1100} = 1}$

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Help Please. Can't seem to understand how to do this. I have tried and watch over 5 videos. Can't seem to get it.​

Help Please. Can't seem to understand how to do this. I have tried and watch over 5 videos. Can't seem to get it.