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Feliz [49]
3 years ago
7

Please Help with this problem

Mathematics
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer:

PD = 30

Step-by-step explanation:

2 secants intersect inside a circle the product of their parts are equal, that is

20(2x + 3) = 18(2x + 6) ← distribute both sides

40x + 60 = 36x + 108 ( subtract 36x from both sides )

4x + 60 = 108 ( subtract 60 from both sides )

4x = 48 ( divide both sides by 4 )

x = 12

Hence

PD = 2x + 6 = (2 × 12 ) + 6 = 24 + 6 = 30

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4 years ago
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Check the picture below.

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because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
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\\\\\\
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\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

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Answer:

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Step-by-step explanation:

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