Answer: THe last one.
Step-by-step explanation:
This question is, in essence, basically asking which numbers are less than -3. Looking at the numbers, it is clearly the last set.
Explanation:
f(x) = (x-4)(x+2)
1) For x-intercept, y will be 0
<u />
<u>x-intercept</u>: (4, 0), (-2, 0)
2) For vertex: x = -b/2a where ax² + bx + c
<u>Quadratic function</u>:
<u>vertex</u>:
y: (x-4)(x+2) = (1-4)(1+2) = -9
ordered pair of vertex: (1, -9)
3) For y-intercept, x will be 0
<u>y-intercept</u>: (0, -8)
Answer:
-46
Step-by-step explanation:
5 (x - 2) - 14x. x=4
5 (4 - 2) - 14(4) (distribute)
20 - 10 - 14(4) (multiply)
20 - 10 - 56 (subtract and solve.)
10 - 56 = -46 - solution
hope this helps (:
I'm guessing you're given the function
, and you're asked to find the inverse function
. To do this, swap
and
, then solve for
:
![x=2-y^3\implies y^3=2-x\implies y=(2-x)^{1/3}=\sqrt[3]{2-x}](https://tex.z-dn.net/?f=x%3D2-y%5E3%5Cimplies%20y%5E3%3D2-x%5Cimplies%20y%3D%282-x%29%5E%7B1%2F3%7D%3D%5Csqrt%5B3%5D%7B2-x%7D)
so that the inverse function is
![y^{-1}(x)=\sqrt[3]{2-x}](https://tex.z-dn.net/?f=y%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7B2-x%7D)
Just to verify:
![y(y^{-1}(x))=y(\sqrt[3]{2-x})=2-(\sqrt[3]{2-x})^3=2-(2-x)=x](https://tex.z-dn.net/?f=y%28y%5E%7B-1%7D%28x%29%29%3Dy%28%5Csqrt%5B3%5D%7B2-x%7D%29%3D2-%28%5Csqrt%5B3%5D%7B2-x%7D%29%5E3%3D2-%282-x%29%3Dx)
![y^{-1}(y(x))=y^{-1}(2-x^3)=\sqrt[3]{2-(2-x^3)}=\sqrt[3]{x^3}=x](https://tex.z-dn.net/?f=y%5E%7B-1%7D%28y%28x%29%29%3Dy%5E%7B-1%7D%282-x%5E3%29%3D%5Csqrt%5B3%5D%7B2-%282-x%5E3%29%7D%3D%5Csqrt%5B3%5D%7Bx%5E3%7D%3Dx)
But in case you're actually only interested in computing the square root, first we note that
(the real-valued square root) is only defined as long as
. So
is defined as long as
, or
, or equivalently
. Under this condition, we could write

We can simplify this further, but we have to be careful. Suppose
. Then
. But we get the same result if
, since
. There are two possible values of
that given the same value of
, so to capture both of them, we take
, the absolute value of
. Then

We can't simplify the square root term further than this.
Answer: its C
Step-by-step explanation: