Answer:
There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.
Step-by-step explanation:
There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

Applying these values on the first equation, we have:

Applying z to the formulas of y and x, we have:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.
Answer:
Step-by-step explanation:
it has no solutions b/c the lines are parallel...but at a different offset.. so they never cross
Answer:
the answer is going to be 496,000. If you meant "Thousandth" and not "Thousand" the answer is going to be 496,179.784
Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg