What shapes can you use to model the log and the board
1 answer:
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Answer:
8.12
Step-by-step explanation:
We obtain the distance between x and y
d = sqrt[(x2 - x1)² + (y2 - y1)²]
d = sqrt[(1 - 2)² + (2 - 6)²]
d = sqrt[1 + 16)
d = sqrt(17)
d² = 17
From Pythagoras rule;
Hypotenus = sqrt(Adjacent² + opposite²)
Hence,
Hypotenus = sqrt(17 + 7²)
Hypotenus = sqrt(17+ 49)
Hypotenus = sqrt(66)
Hypotenus = 8.124
Hypotenus = 8.12
