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goblinko [34]
3 years ago
14

Which absolute value function defines this graph?

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0
If you describe the graph as a V with its vertex point on (0,0), then you are either describing the graph of y = |x| or y = 3|x|. The only difference is that the coordinates of y=3|x| is multiplied thrice the coordinates of y=|x|. In other words, this graph is thrice wider than the y=|x|.

Furthermore, <span>y = -3|x| is a downward V, and
</span>x = |y| and <span>x = 3|y| looks like a V rotated side-ward,</span><span>
</span>
You might be interested in
Suppose that 13 inches of wire costs 52 cents. At the same rate, how many inches of wire can be bought for 32 cents?
kirill115 [55]

Answer:

So we have a ratio which you have specified 13:52. So we just need to get the same ratio for 13. 32/52 is how we get 32 from multiplying by 52. So now we just need to multiply it for 13 also'

13*32/52 = 8. Therefore the answer to this is 8

<h2 /><h2><u>8 is answer</u></h2>
8 0
2 years ago
So lost please help me out with this question
mixas84 [53]
I cannot see the problem
6 0
3 years ago
The lyric, "Historians research more than just the word of one/To learn all sides of history" most closely means that
Ymorist [56]

Answer:

I would say C

Step-by-step explanation:

I said C because when people look for information they look at different sources instead of just one.

8 0
2 years ago
Ten(10) adults and 3 children attend a local concert for $59. Four(4) adults and 3
gladu [14]

Answer:

$5 per adult and $3 per kid

Step-by-step explanation:

5x10=50

3x3=9

50+9=59

4x5=20

3x3=9

20+9=29

4 0
3 years ago
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true
IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.85

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 20

            \mu = true average porosity

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                     of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.85-1.96 \times {\frac{0.75}{\sqrt{20} } } , 4.85+1.96 \times {\frac{0.75}{\sqrt{20} } } ]

                                            = [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.56

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 16

            \mu = true average porosity

<em>Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 98% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-2.3263 < N(0,1) < 2.3263) = 0.98  {As the critical value of z at 1% level

                                                   of significance are -2.3263 & 2.3263}  

P(-2.3263 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} <  2.3263 ) = 0.98

P( \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } } , 4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } } ]

                                            = [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0
3 years ago
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