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3 years ago

10

Question 2 (4 points)

1 answer:

Volgvan3 years ago

5 0

Answer:

43

Step-by-step explanation:

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Which equation represents a line that passes through (–2, 4) and has a slope of ? y – 4 = 2/5(x + 2) y + 4 = 2/5(x – 2) y + 2 =

valentinak56 [21]

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ -2}}\quad ,&{{ 4}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{2}{5}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-4=\cfrac{2}{5}[x-(-2)]
\\\\\\
y-4=\cfrac{2}{5}(x+2)$

7 0

3 years ago

Rewrite the function W= 50+2.3(h-60) in order to express height as a function of weight

OLga [1]

You need to solve the equation for h.

<span>W= 50+2.3(h-60)

Distribute the 2.3.

W = 50 + 2.3h - 138

W = 2.3h - 88

Add 88 to both sides.

W + 88 = 2.3h

Switch sides.

2.3h = W + 88

Divide both sides by 2.3.

h = (W + 88)/2.3
</span>

5 0

3 years ago

Find x. Round to the nearest degree.

jeka94

The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.

We want angle x, which is opposite the side of length 39.

Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x

or 1521 = 3481 + 1296 - 2(36)(59) cos x

Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x

-3256 = -4248cos x

-3256

Then: cosx = --------------- = 0.766

-4248

Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)

5 0

3 years ago

Which statement is true?

love history [14]

<h2>Hello!</h2>

The answer is:

The second option,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Why?</h2>

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}$

<h2>Second option,</h2>

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

The statement is true, we can prove it by using the following properties of exponents:

$(a^{b})^{c}=a^{bc}$

$\sqrt[n]{x^{m} }=x^{\frac{m}{n} }$

We are given the expression:

$(\sqrt[m]{x^{a} } )^{b}$

So, applying the properties, we have:

$(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }$

Hence,

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

<h2>Third option,</h2>

$a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}$

<h2>Fourth option,</h2>

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}$

The statement is false, the correct form of the statement (according to the property of roots) is:

$\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }$

Hence, the answer is, the statement that is true is the second statement:

$(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }$

Have a nice day!

6 0

3 years ago

Help me plssss!!!!!!!

Nookie1986 [14]

<h3> zor bir soru cevap Ceyhan</h3>

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3 years ago