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Shtirlitz [24]
3 years ago
9

What is the additive inverse of -3 *A 3B 4C -3D 0

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0
A. 3 
The additive inverse is the number you add to the one you already have to get it equal to zero.
Anika [276]3 years ago
4 0
The answer is A. positive 3.
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A researcher identifies a sample of teenagers and chooses two males, age 16
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I thinks it is matching pairs for random assignment on gender, age, & income status but I’m not sure
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Calculate the length of the hypotenuse
alexira [117]

Answer:

8.60

Step-by-step explanation:

A^2+B^2=C^2

5*5=25    7*7=49    49+25= 74

√ 74=  8.602...

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4 years ago
Solve the inequality -2(z + 5) + 20 7 6.
Romashka-Z-Leto [24]

Answer:

z<2

Step-by-step explanation:

-2(z + 5) + 20 > 6

Subtract 20 from each side

-2(z + 5) + 20 -20 > 6-20

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Divide each side by -2 remembering  to flip the inequality

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Subtract 5 from each side

z+5-5 < 7-5

z<2

8 0
3 years ago
Read 2 more answers
Rewrite 2 7/9 as a improper fraction
Alborosie
The answer would be 25/9 as a improper fraction
6 0
3 years ago
Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so
xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.

Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

\frac{5}{8} ÷\frac{3}{4}

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

\frac{5}{8}÷\frac{3}{4}=\frac{5}{8}×\frac{4}{3} =\frac{20}{24}

If we simplify this last expression we have:

\frac{20}{24}=\frac{10}{12}  =\frac{5}{6}

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

6 0
4 years ago
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