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3 years ago

Find the difference in numbers 1-6

Mathematics

1 answer:

garri49 [273]3 years ago

8 0

Answer:

Step-by-step explanation:

6-1 is 5

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Which one should I choose

shutvik [7]

Answer:

-32

Step-by-step explanation:

((−4)(4))(2)

=−32

8 0

2 years ago

Read 2 more answers

Noah says that 9x − 2x + 4x is equivalent to 3x because the subtraction sign tells us to subtract everything that comes after 9x

Genrish500 [490]

Answer:

Noah's claim is correct

Step-by-step explanation:

B O D M A S - Brackets, Over, Division, Multiplication, Addition and Subtraction, this means that you must do the addition first.

2x+ 4x = 6x

9x - 6x = 3x

Noah is correct as the - sign tells us that you have to subtract everything after the 9x

Hope this is ok and helps a little bit

5 0

2 years ago

A pile of sand has been stored in the shape of a cone. Mr. Terwilliker knows that the pile is 20 feet tall and 102 feet in circu

xenn [34]

Answer:

The area of tarpaulin is 1315.63 ft^2.

Step-by-step explanation:

height, h = 20 feet

circumference, C = 102 feet

Let the radius is r.

Circumference, C = 2 x 3.14 x r = 102

r = 16.24 feet

Let the slant height is L.

$L = \sqrt{h^2 + r^2}\\\\L = \sqrt{20^2 + 16.24^2}\\\\L = 25.8 ft$

The curved surface area is

S = 3.14 x r x L

S = 3.14 x 16.24 x 25.8 = 1315.63 ft^2

4 0

2 years ago

An atom has 3 protons and 4 neutrons and 2 electrons, what is the overall charge on this atom

Lubov Fominskaja [6]

Answer:

Step-by-step explanation:

Each Proton is +1

Each Neutron is 0

Each Electron is -1

1+1+1+0+0+0+0-1-1=1

4 0

2 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

2 years ago

Find the difference in numbers 1-6​

Find the difference in numbers 1-6