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Gnesinka [82]
3 years ago
9

The length of the base and the height of a triangle are numerically equal. Their sum is 6 less than the number of units in the a

rea of the triangle. Find the area of the triangle.
Mathematics
1 answer:
Troyanec [42]3 years ago
6 0
Base = Height, Let them be x.

( x \times x) \div 2 = (x + x) + 6 \\ x ^{2} \div 2 = 2x + 6 \\ \frac{1}{2} x^{2} - 2x - 6 = 0
Solve quadratic equation:
x=6, x=-2(rejected because base and height is positive)

6x6/2 =18
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3 Write a numerical expression to model the words. Subtract 1 from the product of 4 and 5.​
umka21 [38]

Answer:

Hello!

After reading the question you have provided I have come up with the correct numerical expression:

4x5-1

Step-by-step explanation:

To come up with this solution you need to keep in mind some of the terminoloy being used.

The word "subtract" comes from the action of subtraction

The word "product" comes from the action of multiplication

Thus, using those terminologies correctly, you can then deduce that when the question says "the product of 4 and 5" means "multiplying 4 and 5 together".

So you get the first part being 4x5

Then, you add in the last part of "subract 1" from the "product of 4 and 5":

4x5-1

<em>Remember to keep in mind the rule of "PEMDAS"</em>

You always need to keep the multiplication portion of the equation in front of any subtraction, or addition in any given equation.

7 0
2 years ago
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If f(x) = 6x – 1 and g (x) = StartFraction x + 1 Over 6 EndFraction, which expressions can be used to verify g(x) is the inverse
tigry1 [53]

Answer:

(6 x - 1) + 1 over 6   &

6 ( x + 1 Over 6 ) - 1

Step-by-step explanation:

Edge2020

5 0
3 years ago
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4. Select all the expressions that are less than 3,467.
pav-90 [236]
I think the only answer is E
7 0
3 years ago
PLEASE HELP! Find the distance between each pair of points. Round your answers to the nearest tenth.
strojnjashka [21]
A.
Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\  = \sqrt{\left( -4 - \left( -5 \right) \right)^2 + \left( -2 - \left( -3 \right) \right)^2} \\ \\  = \sqrt{ 1 + 1} \\ \\ = \sqrt{ 2 }

b. 
Distance = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\\\\ = \sqrt{\left( -4 - \frac{ 7 }{ 2 } \right)^2 + \left( \frac{ 5 }{ 2 } - 1 \right)^2} \\  \\= \sqrt{ \frac{ 225 }{ 4 } + \frac{ 9 }{ 4 }} \\ \\=  3 \frac{\sqrt{ 26 }}{ 2 }
6 0
3 years ago
What is the 100th term of the sequence with a1=222 and d=-5
shusha [124]

Answer:

--273

Step-by-step explanation:

100th term is equal a1 + 99d so

100th term = 222 + (-5×99) = -273

6 0
3 years ago
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