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murzikaleks [220]
3 years ago
8

Simplify 6/6^1/4 rational exponents

Mathematics
1 answer:
White raven [17]3 years ago
7 0

Answer:

we conclude that:

\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}

Step-by-step explanation:

Given

The expression is

  • \frac{6}{6^{\frac{1}{4}}}

To determine

Simplify the expression

Simplifying the expression

\frac{6}{6^{\frac{1}{4}}}

Apply the exponent rule:   \frac{x^a}{x^b}=x^{a-b}

\frac{6}{6^{\frac{1}{4}}}=6^{1-\frac{1}{4}}

Subtract the numbers:   1-\frac{1}{4}=\frac{3}{4}

     =6^{\frac{3}{4}}

Therefore, we conclude that:

\frac{6}{6^{\frac{1}{4}}}=6^{\frac{3}{4}}

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 angle x would end up being equal to 71 degrees.
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3 years ago
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-2(bx - 5) = 16<br><br> What’s does b and x equal?
horrorfan [7]
To solve this problem you must apply the proccedure shown below:
 You have the following equation given in the problem above:
 <span>-2(bx - 5) = 16
</span> When you solve for bx, you have:
 <span>-2(bx - 5) = 16
 -2bx-10=16
 -2bx=26
 bx=26/-2
 bx=-13

 When you solve for b, you obtain:
 </span><span>-2(bx - 5) = 16
 -2bx=26
 b=-(26/2x)

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3 0
3 years ago
Please help me out man<br><br> f/ 6 = 17
ratelena [41]

Answer:

f/6=17

f=17×6

=102

Hope it helps!!!

7 0
2 years ago
Read 2 more answers
LaTesha and Bernard are playing a game. Their scores for five games are shown in the table below. LaTesha’s and Bernard’s Scores
andre [41]

Answer:

The means differ by 1, but the ranges differ by 40.

Step-by-step explanation:

The mean for LaTesha's score is (92+45+67+36+80)/5= 64

The mean for Benards score is (63+68+62+69+53)/5= 63

The range for LaTeshas score is 92-36=56

The range for Benards score is 69-53=16

So, 64-63=1     and        56-16= 40

6 0
3 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
maxonik [38]

Answer:

Total weight of the wheat placed on 45th square will be = 1.26\times 10^{6}tons

Step-by-step explanation:

King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one  grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = a(r^{n-1})

where a = first term of the series, r = common ratio, n = number of terms

Now we have to calculate the weight of all wheat placed on 45th square.

So we will put the values in the given formula 45th term =

1\times (2^{45-1}) = 2^{44}=1.76\times 10^{13}

Then the weight of wheat will be = 2.51\times 10^{9}pounds=1.26\times 10^{6}tons



7 0
3 years ago
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