Mean because all of the data points are
fairly close and there aren't any outliers
(extreme values)
So the diagonal of cube
this was a practice act question so her's the answer
look at the cube through one of the faces
you will see the diagonal as the hypotonuse of a triangle
and also a triangle on the floor (look at attachment)
the ,diagonal is 28
a^2+b^2=28^2
a=b since it is a cube
remember that this is a 45,45 triangle so therefor
a=b=x
c=x√2 so
28=x√2
divide both sides by √2
28/(√2)=x
the diagonal on the floor is 28/(√2)
the sides of the triangle form another 45 45 90 triangle with 28/(√2) as hyponuse so
a=b=x
c=x√2=28/(√2)
solve for x
x√2=28/(√2)
divide both sides by √2
same as mujlitply both sides by 1/(√2) so
28/(√2) times 1/(√2)=28/(2)=14
the answer of 1 diagonal is 14 cm
the answer is 14cm
(12x^3-4x^2+8x)/(-2x) The greatest common factor of the numerator and denominator is -2x so upon division by GCF of both numerator and denominator you have:
-6x^2+2x-4 and we can now also factor out -2
-2(3x^2-x+2)
x= 7/13. Hope I helped you !!!!