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3 years ago

You are holding the axle of a bicycle wheel with radius

Physics

1 answer:

erastova [34]3 years ago

6 0

Answer:

The angular acceleration of the wheel is -6.54 rad/s²

Explanation:

We'll use the equations of motion for this.

w = 2πf

f = 75 rpm = 1.25 rps = 1.25 rev/s

w₀ = initial angular velocity = 2π × 1.25 = 7.85 rad/s

w = final angular velocity = 0 rad/s

t = 1.2 s

α = ?

w = w₀ + αt

0 = 7.85 + 1.2α

α = 7.85/1.2 = - 6.54 rad/s²

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A 95 kg clock initially at rest on a horizontal floor

Nataly [62]

Answer:

You are given that the mass of the clock M is 95 kg.

This is true whether the clock is in motion or not.

Fs is the frictional force required to keep the clock from moving.

Thus Fk = uk W = uk M g the force required to move clock at constant speed. (the kinetic frictional force)

uk = 560 N / 931 N = .644 since the weight of the clock is 931 N (95 * 9.8)

us is the frictional force requited to start the clock moving

us = static frictional force = 650 / 931 -= .698

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3 years ago

True or False? In an RL circuit, the larger the value of R (i.e. the resistance of the circuit), the longer it takes the circuit

Luba_88 [7]

Answer:

1.False

2.4 E

Explanation:

1.We have to find the statement is true or false.

We know that

Time constant, $\tau=\frac{L}{R}$

Time constant is inversely proportional to resistance R .It means when R increases then time constant decreases when R decrease then the time constant decreases.

Statement:The larger the value of R ,the longer it takes the circuit to reach its final steady- state value

It is false.

2.Energy stored in inductor,E= $\frac{1}{2}LI^2$

When I'=2I

Then, $E'=\frac{1}{2}L(2I)^2=\frac{1}{2}LI^2\times 4=4 E$

Hence,the new total energy will become 4 E.

3 0

3 years ago

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xz_007 [3.2K]

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5 0

2 years ago

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Feliz [49]

Answer:

Explanation:

5 0

3 years ago

An electric motor has an effective resistance of 22 22 and an inductive reactance of 72 12 when working under load. The voltage

Alecsey [184]

Answer:

Current amplitude, I = 5.57 A

Explanation:

It is given that,

Effective resistance, R = 22 ohms

Inductive reactance, L = 72 ohms

Voltage of the alternating source, V = 420 volt

The total impedance of the RL circuit is given by :

$Z=\sqrt{R^2+L^2}$

$Z=\sqrt{(22)^2+(72)^2}$

Z = 75.28 ohms

From Ohm's law,

$V=I\times Z$

$I=\dfrac{V}{Z}$

$I=\dfrac{420}{75.28}$

I = 5.57 A

So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.

6 0

3 years ago