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Irina-Kira [14]
3 years ago
14

The energy of a photon was found to be

Physics
2 answers:
maria [59]3 years ago
6 0

Answer:

Green.....

Explanation:

.....

Vaselesa [24]3 years ago
4 0

now you can yourself know to which part of electromagnetic spectrum the photon belongs....

not fitting sharply in green

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The amount of steering wheel movement needed to turn will ____________ the faster you go.
Naddika [18.5K]

Answer:

The answer to your question is Decrease

4 0
3 years ago
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What is the unit of work in SI system?
Citrus2011 [14]

Answer:

Joule ;)

Explanation:

In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work.

Hope this helps!

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3 years ago
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Observe and compare the forces acting on the turtle and the cat.
Pepsi [2]

Answer:

The forces are balanced on both animals because they are not moving

More importantly than not moving is not <u>accelerating.</u>

Explanation:

5 0
2 years ago
1.Predict the frequency of a tuning fork that emits a sound with a wavelength of 0.385 m.
lina2011 [118]

Answer:

1.) Frequency F = 890.9 Hz

2.) Wavelength (λ) = 0.893 m

Explanation:

1.) Given that the wavelength = 0.385m

The speed of sound = 343 m / s

To predict the frequency, let us use the formula V = F λ

Where (λ) = wavelength = 0.385m

343 = F × 0.385

F = 343/0.385

F = 890.9 Hz

2.) Given that the frequency = 384Hz

Using the formula again

V = F λ

λ = V/F

Wavelength (λ) = 343/384

Wavelength (λ) = 0.893 m

The two questions can be solved with the use of formula

3 0
3 years ago
An object whose specific gravity is 0.850 is placed in water. What fraction of the object is below the surface of the water?
Fynjy0 [20]

Answer:

The fraction of the object that is below the surface of the water is ¹⁷/₂₀

Explanation:

Given;

specific gravity of the object, γ = 0.850

Specific gravity is given as;

specific \ gravity = \frac{density \ of the \ object}{density \ of \ water}\\\\0.85= \frac{density \ of the \ object}{1000 \ kg/m^3} \\\\density \ of the \ object = 850 \ kg/m^3

Fraction of the object's weight below the surface of water is calculated as;

= \frac{850}{1000} \ \times\ 100\%\\\\= 85 \% \\\\= \frac{17}{20}

Therefore, the fraction of the object that is below the surface of the water is ¹⁷/₂₀

8 0
3 years ago
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