3 years ago

The ordered pair of (3,-2) would be located in which quadrant

Mathematics

1 answer:

agasfer [191]3 years ago

8 0

It would be located in quadrant 4 because it has to be positive and negative.

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PLEASE HELP I've tried everything 30 points!

Luda [366]

Answer:

(x+2)1x-8)=0

x=-2 or x=8

Step-by-step explanation:

The given quadratic expression is

$2 {x}^{2} - 12x - 32$

We equate this expression to zero to get:

$2 {x}^{2} - 12x - 32 = 0$

Let us divide through by 2 to get:

${x}^{2} - 6x - 16 = 0$

Split the middle term to get:

${x}^{2} - 8x + 2x - 16 = 0$

Factor

${x}(x - 8) + 2(x - 8) = 0$

Factor further to get

$(x - 8)(x + 2) = 0$

The solution are

$x = - 2 \: and \: x = 8$

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

The ordered pair of (3,-2) would be located in which quadrant​

The ordered pair of (3,-2) would be located in which quadrant