How does a straight-chain alkane that has five carbon atoms differ from a cycloalkane that has five carbon atoms?
2 answers:
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Answer:
Explanation:
For each of these molecules, you must determine their VSEPR structure and then identify the strongest intermolecular forces.
Remember that water is a highly polar molecule.
a) CH₄
Electron geometry: tetrahedral
Molecular geometry: tetrahedral
Bond polarity: C-H bond nonpolar
Molecular polarity: nonpolar
Strongest IMF: London dispersion forces
Solubility in water: low
A nonpolar molecule is insoluble in a polar solvent.
b) CCl₄
Electron geometry: tetrahedral
Molecular geometry: tetrahedral
Bond polarity: C-Cl bond nonpolar
Molecular polarity: nonpolar (symmetrical molecule. All bond dipoles cancel)
Strongest IMF: London dispersion forces
Solubility in water: low
A nonpolar molecule is insoluble in a polar solvent.
d) PH₃
Electron geometry: tetrahedral
Molecular geometry: trigonal pyramidal
Bond polarity: P-H bonds are polar
Molecular polarity: polar (all P-H bond dipoles point towards P)
Strongest IMF: dipole-dipole
Solubility in water: soluble
A polar molecule is soluble in a polar solvent.
c) NH₃
Electron geometry: tetrahedral
Molecular geometry: trigonal pyramidal
Bond polarity: N-H bonds are highly polar
Molecular polarity: highly polar (all N-H bond dipoles point towards N)
Strongest IMF: hydrogen bonding
Solubility in water: highly soluble
NH₃ is so polar that it can form hydrogen bonds with water.
The amount of KCl that would be formed will be 478.8 grams
<h3>Stoichiometric calculations</h3>From the equation of the reaction, the mole ratio of K to is 2:1.
Mole of 309 g potassium = 309/39 = 7.92 moles
Mole of 228 g Cl2 = 228/71 = 3.21 moles
Thus, potassium is in excess while Cl2 is limiting.
Mole ratio of Cl2 and KCl = 1:2
Equivalent mole of KCl = 3.21 x 2 = 6.42 moles
Mass of 6.42 moles KCl = 6.42 x 74.55 = 478.8 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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