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WARRIOR [948]
4 years ago
6

The equilibrium concentrations for the reaction between SO2 and O2 to form SO3 at a certain temperature are given in the table b

elow. Determine the equilibrium constant and whether the reaction favors reactants, products, or neither at this temperature.

Chemistry
1 answer:
Nadya [2.5K]4 years ago
6 0

Answer:

Option B. K = 1.3×10⁴, product favored

Explanation:

Data obtained from the question include:

O2(g) + 2SO2(g) <==> 2SO3(g)

Concentration of O2, [O2] = 0.024 M

Concentration of SO2, [SO2] = 0.015 M

Concentration of SO3, [SO3] = 0.26 M

Equilibrium constant, K =..?

The equilibrium constant, K is simply defined as the ratio of the concentration of products raised to their coefficient to the concentration of the reactants raised to their coefficient.

The equilibrium constant for the above reaction can be written as

K = [SO3]² / [O2] [SO2]²

Inputing the values of [SO3], [O2] and [SO2] the equilibrium constant, K is:

K = [SO3]² / [O2] [SO2]²

K = 0.26² / 0.024 × 0.015²

K = 1.3×10⁴

Therefore, the equilibrium constant K is 1.3×10⁴.

Since the value of the equilibrium constant, K is large and positive, therefore, the reaction favours the product.

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Answer:

The answer is

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Explanation:

The pressure exerted by an object given the force of the object and the area can be found by using the formula

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From the question

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P =  \frac{2400}{0.4}  \\

We have the final answer as

<h3>6000 N/m² or 6000 Pa</h3>

Hope this helps you

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