Answer:
Water
Explanation:
Given the specific heat of oxygen is 918J/kg°C and the specific heat of water is 4181 J/kg°C.
Consider 1Kg mass of each substance.
Now 1 Kg of oxygen needs 918 J of energy to raise its temperature by 1°C
Also 1 Kg of water needs 4181 J of energy to raise its temperature by 1°C.
Clearly water recquires more energy when compared to oxygen.
Basically specific heat capacity is the amount of energy recquired to raise the temperature of a 1 kg body by 1°C.
The mass of one gram of starch is 7.7143. You find the molecular mass for each elmement on the table and multiply by the little number beside it(the number of each of the elements in the compound) and then add all the numbers together and divide by the total of all the little numbers
I haven't done these in some time, so I'm not sure if they are 100% right.
1) 6.3 moles of H2( 2 mol of NH3 / 3 mol of H2)= 4.2 mol of NH3
6.3 moles of H2( 2 mol of NH3/ 3 mol of H2)(17.04 g of NH3/1 mol NH3)= 71.57 g of NH3
2) 2.5 moles of N2(2 mol of NH3/1 mol of N2)= 5 moles of NH3
2.25 moles of N2(2 mol of NH3/ 1 mol of N2)(6.02x10^23 particles/ 1 mol of NH3)= 3.01x10^24 particles of NH3
3) 425 g of NH3(1 mol of NH3/17.04 g NH3)= 24.9 moles of NH3
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)(28.02 g of N2/1 mol N2)= 349 g of N2
425 g of NH3(1 mol of NH3/17.04 g of NH3)(1 mol of N2/2 mol of NH3)= 12.5 mol of N2
4) 10 moles NH3(3 moles of H2/2 moles of NH3)= 15 moles H2
10 moles NH3(3 mol of H2/2 mol of NH3)(2.02 g of H2/1 mol of H2)= 30.3 g of H2
30.3 g = .0303 liters of H2
Answer:
Explanation:
N₂ + 3 H₂ → 2 NH₃
1 mole 3 moles 2 moles
3.45 moles 10.35moles 6.90 moles
So 3.45 moles of nitrogen will require 10.35 moles of hydrogen
But hydrogen available is only 4.85 so this gas is the limiting reagent and product will be formed according to its mass .
a )
3 moles of hydrogen can form 2 moles of ammonia
4.85 moles of hydrogen will form 2 x 4.85 / 3 moles of ammonia
= 3.23 moles .
b ) hydrogen is the limiting reagent .
c ) Excess reactant is nitrogen
3 moles hydrogen need 1 mole of nitrogen
4.85 moles of hydrogen will need 4.85 / 3 moles of nitrogen
= 1.62 moles of nitrogen .
excess nitrogen = 3.45 - 1.62
= 1.83 moles.
