3 years ago

What is the range of y =|3x + 1|?

Mathematics

2 answers:

marysya [2.9K]3 years ago

8 0

Answer:

Y | Y > 0

Step-by-step explanation:

The absolute value expression has a v shape. The range of a positive absolute value expression starts at its vertex and extends to infinity

stiks02 [169]3 years ago

3 0

Answer:

c) {y | | y≥13}

Step-by-step explanation:

I think you guys are doing an inverse operation, so you would be dividing the equation. That's the only explanation I can provide...sadly.

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GrogVix [38]

Answer: $5x^2-x+4$

Step-by-step explanation:

In addition of polynomials, you only have to add the like terms.

Remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-$

Then, given the polynomial $12x^2+3x+6$ and the polynomial $-7x^2-4x-2$ , you can find the sum of them by adding the like terms.

Observe the procedure below:

$(12x^2+3x+6)+(-7x^2-4x-2)=12x^2+3x+6-7x^2-4x-2=5x^2-x+4$

Therefore, the sum is:

$5x^2-x+4$

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