F(x) = kx
12 = 8k
k = 12/8 = 3/2
Required equation is f(x) = 3/2 x
Answer:
value of x = 5.8 mm
Step-by-step explanation:
We have given,
Two right triangles EDH and EDG.
In right triangle EDH, EH = 56mm , DH = 35 mm
Using Pythagoras theorem we can find ED.
i.e EH² = ED²+DH²
56²=ED²+35²
ED²=56²-35²
ED = √(56²-35²) = 7√39 = 43.71 mm
Now, Consider right triangle EDG
Here, EG=44.8mm , GD = x+4 and ED = 7√39
Again using Pythagoras theorem,
EG² = ED² + DG²
44.8²= (7√39)²+ (x+4)²
(x+4)² = 44.8² - (7√39)²
x+4 = √(44.8² - (7√39)²)
x+4 = 9.8
or x = 9.8 - 4 = 5.8 mm
Hence we got the value of x = 5.8 mm
Answer: The solution is,
or 
Step-by-step explanation:
Given compound inequality,
-8x + 14 ≥ 60 or -4x + 50 < 58,
By the subtraction property of inequality,
-8x + 14 - 14 ≥ 60 - 14 or -4x + 50 - 50 < 58 -50,
-8x ≥ 46 or -4x < 8
By the division property of inequality,
or 
Using property a > b ⇒ - a < -b,
or
B. One arm extended straight to the side
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2 x (n - 6)
(2 x n - 2 x 6)
(2n - 2 x 6)
2n - 12
