Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore


1st is parallel
2nd is perpendicular
3rd is perpendicular
4th is perpendicular
Multiply both sides by d.
dm=a+64d
Flip the equation.
a+64d=dm
Add -64d to both sides.
a=dm−64d
Answer:
<u>a=dm−64d</u>
Answer:
8
Step-by-step explanation:
write numbers in numerical order then subtract the highest number from the lowest number and you get the range.
(1,2,3,3,4,4,6,9)
9 - 1 = 8