What number is 80% of 500

Mathematics

2 answers:

Andre45 [30]2 years ago

3 0

It would be 400. Hope this helped. :)

zavuch27 [327]2 years ago

3 0

80% of 500 is 400. Hope this helps!!!

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Prove that : 1/1-secA + 1/1+secA = -2cot^2A

irina1246 [14]

Answer:

Step-by-step explanation:

LHS = 1/1-secA + 1/1+secA

$= \frac{1*(1+Sec A)}{(1-Sec A)(1+Sec A)}+\frac{1*(1-Sec A)}{(1+Sec A)*(1-Sec A)}\\\\=\frac{(1+Sec A)}{1-Sec^{2} A}+\frac{(1-Sec A)}{1-Sec^{2} A}\\\\=\frac{1+Sec A+1-Sec A}{(1-Sec^{2} A)}\\\\= \frac{2}{(1-Sec^{2} A)}\\\\=\frac{2}{-(Sec^{2} A - 1)}\\\\= \frac{-2}{Tan^{2} A}\\\\= -2Cot^{2} A$

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2 years ago

The volume of a cylinder is V = 1/3 πr2h. If the radius is doubled and the height is halved, what will be the ratio of the new v

ozzi

<span>V(o) = 1/3 πr²h - old volume
</span>V(n) = 1/3 π(2r)²(h/2)=1/3 π(2r)²(h/2)=1/3*4/2* πr²h=1/3*2* πr²h
V(n)/V(o)=1/3*2* πr²h/1/3 πr²h=2/1
V(n)/V(o)=2/1 - ratio
the volume will be doubled

8 0

3 years ago

Read 2 more answers

There are 30 students in a class that took a test. The average grade of 10 students was 80. The other 20 students average was 89

Vsevolod [243]

10 students averaged 80, so the sum of their scores was (10 x 80) = 800

20 students averaged 89, so the sum of their scores was (20 x 89) = 1,780

All together, the sum of all 30 scores was (800 + 1,780) = 2,580

30 students totaled 2,580, so their average was (2,580 / 30) = <em> 86</em> .

6 0

2 years ago

The final exam of a particular class makes up 40% of the final grade, and Moe is failing the class with an average (arithmetic m

amm1812

Answer:

%82.5

Step-by-step explanation:

The final exam of a particular class makes up 40% of the final grade
Moe is failing the class with an average (arithmetic mean) of 45% just before taking the final exam.

From point 1 we know that Moe´s grade just before taking the final exam represents 60% of the final grade. Then, using the information in the point 2 we can compute Moe´s final grade as follows:

$FG=0.40*FE+0.60*0.45$ ,