Offer B is the best value for money because each kg cost is £0.61 and in offer 'A' each kg cost is £0.7.
<h3>What is a fraction?</h3>
Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
We have:
2 bags for £35
2 bags means 50 kg (2×25)
Each kg cost = 35/50 = £0.7 per kg
3 bags for £92.50
3 bags means 150 kg
Each kg cost = 92.50/150 = £0.61 per kg
As we can see, offer B has a low cost per kg
Thus, offer B is the best value for money because each kg cost is £0.61 and in offer 'A' each kg cost is £0.7.
Learn more about the fraction here:
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Answer:
50000 5000 200 20 2
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
This is because to find the angle you must add up the other two angles.
The answer is -10
just input the numbers where the variables are so your question turns into 5(-4 - -2)
hope this helps!!
Answer:
- P(E) = 1/2
- P(F) = 11/32
- P(G) = 1/6
- P(EF) = 5/52
- P(FG) = 1/32
- P(EG) = 1/6
Step-by-step explanation:
For the sum to be even, both dice can be odd, or both even. The probability of a dice being odd is 1/2 and the same is for it to be even. Since the result of the dices are independent, we have that
P(E) = (1/2)² + (1/2)² = 1/2
Out of the 36 possible outcomes for the dice (assuming that you can distinguish between first and second dice), there are 11 cases in which one dice is a 6 (if you fix 1 dice as 6, there are 6 possibilities for the other, but you are counting double 6 twice, so you substract one and you get 6+6-1 = 11). Since all configurations for the dices have equal probability, we get that
P(F) = 11/32
The probability for the second dice to be equal to the first one is 1/6 (it has to match the same number the first dice got). Hence
P(G) = 1/6
for EF, you need one six and the other dice even. For each dice fixed as 6 we have 3 possibilities for the other. Removing the repeated double six this gives us 5 possibilities out of 32 total ones, thus
P(EF) = 5/32
If one dice is 6 and both dices are equal, then we have double six, as a result there is only one combination possible out of 32, therefore
P(FG) = 1/32
If both dices are equal, in particular the sum will be even, this means that G= EG, and as a consecuence
P(EG) = P(G) = 1/6
