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pshichka [43]
3 years ago
5

The time required to finish a test in normally distributed with a mean of 40 minutes

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

84%.

Step-by-step explanation:

Let X be the time in minutes for a student chosen at random to finish the test.  X\sim N(40, 8^{2}).

The probability that a student chosen at random finishes the test in less than 48 minutes will represented as

P(X< 48).

<h3>Method 1: technology</h3>

Evaluate the cumulative normal probability on a calculator, where

  • The lower bound is 0,
  • The upper bound is 48,
  • The mean \mu = 40,
  • The standard deviation \sigma = 8

P(X < 48) = 0.8413.

<h3>Method 2: z-score table</h3>

x = 48.

\displaystyle z = \frac{x - \mu}{\sigma} = \frac{48 - 40}{8} = 1.

Look up the entry that corresponds to z = 1.000 on a z-score table: 0.8413.

In other words,

P(X < 48) = P(Z < 1) = 0.8413.

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A state license plate consists of three letters followed by three digits. If repetition is allowed, the number of different ways in which license plates are possible is 17,576,000.

<h3>What is a permutation?</h3>

An arrangement of items in a specific order is referred to as a permutation. When the order of the arrangements counts, it is a mathematical technique that establishes the total number of alternative arrangements in a collection.

Calculation for the permutation -

Three letters are followed by three digits on a state license plate.

26 letters from a to z and 10 numbers from 0 to 9 make up the alphabet.

The potential of arrangements is due to the license plate's composition of three letters and three numerals.

Total ways = 26×26×26×10×10×10

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Therefore, the number of different ways in which license plates are possible is 17,576,000.

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How do you solve for the slope of a line with the equation ax^2 + bx + c?
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A bicyclist heads east at 10km/h. After she has traveled 24.2 kilometers, another cyclist sets out in the same direction going 3
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We know that the first cyclist has traveled 24.2 km at a speed of 10 km/h. Lets use the equation time= \frac{distance}{speed} to find the time of the first cyclist:
t= \frac{24.2}{10}
t=2.42
So, we know that she has traveled for 2.42 hours.
 
We also know that after she has traveled for 2.42 hours another<span> cyclist sets out in the same direction, so if </span>t represents the time of our first cyclist, <span>the time of our second cyclist will be </span>t-2.42.

Now we are going to use the equation distance=(speed)(time) to relate the speeds and times of the two cyclist:
For the first one:
distance=10t equation (1)
For the second one:
distance=30(t-2.42) equation (2)

Replace (1) in (2)
10t=30(t-2.42)
The only thing left now is solve for t:
10t=30t-72.6
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t= \frac{-72.6}{-20}
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We can conclude that the second cyclist will catch up the first cyclist after 3.63 hours.


4 0
3 years ago
Susan invests $Z at the end of each year for seven years at an annual effective interest rate of 5%. The interest credited at th
aleksley [76]

Answer:

2.02955

Step-by-step explanation:

Given that:

Susan invests $Z as each year ends for seven years.

So we assume that Z = 1

Susan's accrued value comprises $7 invested each year at a 6 percent annual effective rate.

The cashflow interest:

The cashflow of Susan interest payments are:

Payments   Time

0                     1

0.05               2

2(0.05)           3

3(0.05)           4

4(0.05)            5

5(0.05)            6

6(0.05)            7

The accumulated value of this cash flow is:

(0.05)I_{6\%} = (0.05) \dfrac{((1+0.06)_{6\%} - 6)}{0.06} \\ \\ \implies 1.1653

So Susan accumulated values is:

X = 7 + 1.1653

X = 8.1653

Lori's accumulated value is $14, which she has set aside to plan her cash flow for interest.

The cashflow of Lori interest payments are;

Payments    0     0.025     2(0.025)       3(0.025)    .........   13(0.025)

Time             1        2              3                    4            ..........  14

The accumulated value of cash flow is:

(0.025 )(I)_{3\%} =(0.025) \dfrac{(1+0.03)_{3\%}-13}{0.03}\\ \\= 2.5719

Now, Lori's accumulated value is:

Y = 14 + 2.5719

Y = 16.5719

Since; Susan value X = 8.1653

Lori's value Y = 16.5719

∴

\dfrac{Y}{X}= \dfrac{16.5719}{8.1653}

= 2.02955

7 0
3 years ago
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