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sammy [17]
3 years ago
9

Make a the subject of V^2+U^2+2as

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0
I think you mean v^2 = u^2 + 2as  which is an equation of motion under constant acceleration

2as = v^2 - u^2
a =  (v^2 - u^2) / 2s
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Answer:

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STEP-BY-STEP EXPLANATION:

Given information

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\begin{gathered} (x,\text{ y) }\rightarrow\text{ (x, y-b)} \\ \text{where b = 4} \\ (5,\text{ 0) }\rightarrow\text{ (5, 0 - 4)} \\ (5,\text{ 0) }\rightarrow\text{ (5, -4)} \end{gathered}

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Step 2: Reflect over the y-axis

The general rule for reflecting over the y-axis is (-x, y)

This means the value of x will be negated and the value of y will remain the same

\begin{gathered} \text{Over the y-ax}is \\ (x,\text{ y) }\rightarrow\text{ (-x, y)} \\ (5,\text{ -4) }\rightarrow\text{ (-5, -4)} \end{gathered}

Step 3: the graph the point

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