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sammy [17]
3 years ago
9

Make a the subject of V^2+U^2+2as

Mathematics
1 answer:
denis-greek [22]3 years ago
8 0
I think you mean v^2 = u^2 + 2as  which is an equation of motion under constant acceleration

2as = v^2 - u^2
a =  (v^2 - u^2) / 2s
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20,18,13,17,18 find the mean,median and mode​
Degger [83]
<h3>Answer:</h3>

Mean: 17.2

Median: 18

Mode: 18

<h3>Solution:</h3>

Mean: The sum of all observation divided by several observation

  • 20+18+13+17+18=86
  • 86÷5=
  • 17.2

Median:it is the middlemost observation of data arraged in increasing or decreasing order of values

  • (13,17,18,18,20)
  • (17,18,18)
  • (18)

Mode:it is the value that occurs frequently in a set of data

  • (13 , 17 , 18 , 18 , 20)

Hope it helps

6 0
2 years ago
Read 2 more answers
Describe the solution of g(x) shown in the graph.
Ugo [173]

Answer:

All real solutions

Step-by-step explanation:

  • The given graph is a maximum quadratic function.
  • The solution to the graph is where the graph intersects the x-axis.
  • We can see from the graph that, the function intersected the x-axis at two different points, hence its discriminant is greater than zero.
  • Hence the solution of g(x) are two distinct real solutions.
  • The solutions are not whole numbers because the x-intercepts are not exact.
  • The solutions are also not all points that lie on g(x)
  • The first choice is correct.
3 0
3 years ago
Admission to a county fair is $8 for adults and $5 for children. Find the total cost of admission for 3 adults and 4 children. *
son4ous [18]

Answer:

44$

Step-by-step explanation:

u multiply 8 by 3 and 5 by 4 and you get 24 and 20 and add 24 and 20 and u get 44

4 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
4 years ago
Pleasee anyonnee help me assaaapppp
nekit [7.7K]
30, 34
You add 4 on
44
Because it starts at 10 and 10 cannot be divided by 4
7 0
3 years ago
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