(-3y^2 − 8) − (-5y^2<span> + 1)
= </span>-3y^2 − 8 + 5y^2<span> - 1
= 2</span>y^2 <span>- 9
answer is
</span>2y^2 - 9<span>
</span>
To find the length of a square given the area, we just need to take the square root of the area given. The sqrt of 36 is 6, so each side is 6 inches. :)
Answer:
the line modeling the baking powder and the flour used
Step-by-step explanation:
plato master test
Answer:
It will be 381. You round up if it is five and over, and round down if 5 and below.
Step-by-step explanation:
A decimal cannot be a whole number so rounding to the nearest whole number means getting rid of the decimal. You do this by rounding up if it 5 and up, and rounding down if it is 5 and below. 380.5 means you would round up to 381. If it it were 380.4, you would round down to 380.
Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------
Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width
