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ruslelena [56]
3 years ago
13

125% of what is 85.And 350% of what is 679.Please help meee.

Mathematics
2 answers:
Reil [10]3 years ago
6 0
125% of 68 is 85 
350% of 194 is 679 

const2013 [10]3 years ago
3 0
125% equals to be 1.25 in decimal form. You do 85 / 1.25 and get 68. Next one 350% is 3.50 in decimal form. You do 679 / 3.50 which is 194.
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A pile of sand has a weight of 90 kg the sand is put into a small bag a medium bag and a large bag in the ratio 2:3:7
romanna [79]

Answer:

15 kg, 22.5 kg, 52.5 kg

Step-by-step explanation:

Let the common multiplier of the given ratios be x. Therefore, weights of each bag would be 2x, 3x and 7x

According to the given information:

2x + 3x + 7x = 90 \\ 12x = 90 \\ x =  \frac{90}{12}  \\ x = 7.5 \:  \\  \implies \\ 2x = 2 \times 7.5 = 15 \: kg \\ 3x = 3 \times 7.5 = 22.5 \: kg \\ 7x = 7 \times 7.5 = 52.5 \: kg

Hence the weight of sand in bag would be 15 kg, 22.5 kg and 52.5 kg

3 0
3 years ago
Which of the following represents the area of a rectangle whose length is x − 7 and whose width is x + 12?
Zarrin [17]
(x-7)(x+12)
X^2 +12x-7x-84

x^2+5x-84. <- answer
8 0
4 years ago
Read 2 more answers
A car is traveling at 78 miles per hour in a zone with a speed limit of 60 miles per hour. A police officer writes a ticket whic
OLga [1]

Answer:

Final cost of ticket = $205

Step-by-step explanation:

Speed limit is given: 60 miles per hour

Car travelling at a speed of: 78 miles per hour

Car is exceeding speed limit by: 78 - 60 = 18 miles per hour

We are given that the dine ticket includes $25 plus $10 for each mile over the speed limit:

Final cost of ticket = $25 + (miles over speed limit * 10)

= 25 + (18*10)

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5 0
3 years ago
A company offers a raffle whose grand prize is a $35,000 new car. Additional prizes are a $1,100 television and $600 computer. T
anastassius [24]

Answer:

-$ 10.13

Step-by-step explanation:

Given,

The cost price of each ticket = $ 22,

So, the value of each ticket other than price ticket = - $ 22, ( negative sign shows loss,i.e. if we don't get the price we will have the loss of $ 22 )

Now, there are 3 tickets in which first is of $35,000 price, second is of $1,100 and third is of $ 600,

So, the value of first ticket = 35000 - 22 = $ 34978,

Value of second ticket = 1100 - 22 = $ 1078,

Value of third ticket = 600 - 22 = $ 578,

Also,

\text{Probability}=\frac{\text{Favourable outcome}}{\text{Total outcome}}

Hence, by the above information we can make a table for the given situation,

Number           2997               1                    1                     1        

Price               -$ 22               $ 34978        $ 1078           $ 578

Probability       2997/3000      1/3000         1/3000           1/3000

Therefore, the expected value of a ticket

=-22\times \frac{2997}{3000}+34978\times \frac{1}{3000}+578\times \frac{1}{3000}

=-$10.126

≈ - $ 10.13

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frozen [14]

Answer: 1 & 4

1.25

Step-by-step explanation:

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3 years ago
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