<img src="https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7Bl%2Fg%7D" id="TexFormula1" title="T=2\pi \sqrt{l/g}" alt="T=2\pi \sqrt{

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3 years ago

l/g}" align="absmiddle" class="latex-formula">
This is the formula for the period T of a pendulum of length l. Solve this formula for l.

Mathematics

1 answer:

Ket [755]3 years ago

8 0

Answer:

T^2*g / 4pi^2 = l

Step-by-step explanation:

T = 2 * pi * sqrt( l/g)

We need to solve for l

Divide each side by 2pi

T/ (2pi) = 2 * pi/2pi * sqrt( l/g)

T/ (2pi) = sqrt( l/g)

Now square each side

(T/ (2pi))^2 = ( sqrt( l/g))^2

T^2 / 4pi^2 = l/g

Multiply each side by g

T^2 / 4pi^2 * g= l/g*g

T^2*g / 4pi^2 = l

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