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kodGreya [7K]
4 years ago
6

Which inequality is represented by the graph below?

Mathematics
1 answer:
jasenka [17]4 years ago
3 0

Answer:

y<-2x+1

Step-by-step explanation:

Hope this helps and can I have brainliest!

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Y varies directly affects if y equals negative five when x equals 15 find X when y equals three
Anni [7]
Well,

We are given a direct proportion problem.

x varies directly as y.

\frac{x}{y}

When y = -5, x = 15.
\frac{15}{-5} \ or\  \frac{3}{-1}

Now, we are told to find x when y = 3.

\frac{x}{3}

We just have to recognize that the complete case is equal to the incomplete case.  In other words, we set the -3 equal to the x/3.

\frac{3}{-1} =  \frac{x}{3}

Multiply both sides by the LCM.
LCM of -1 and 3 = 3

-9 = x

When y = 3, x = -9.
6 0
3 years ago
Josh is wrapping a box that is 5 feet long 14 feet wide and 3 feet tall with wrapping paper. How much wrapping paper will he nee
kaheart [24]
Hes gonna need 210 feet of wrapping paper bc 14x5 = 70 and 70x3 =210
4 0
3 years ago
Read 2 more answers
b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
The length of a garden is 5m greater than the width. the area is 66m^2. Find the dimensions of the garden.
11Alexandr11 [23.1K]
W^2+5w-66=0 
Factor 
(w+11)(w-6)=0 

w+11=0 
w=-11 (not possible - cant have negative length 

w-6=0 
w=6 

L(6)=66 
L=11 

Width = 6 
Length = 11
8 0
4 years ago
Which of the following is not true in regard to the benefit of statistics? A. Statistics promotes positive change. B. Statistics
Karolina [17]
I would go for answer B
7 0
3 years ago
Read 2 more answers
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