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kakasveta [241]
3 years ago
9

So confused. There is a link to the picture :)

Mathematics
1 answer:
user100 [1]3 years ago
4 0
An = a1 + (n-1)d

an = 27 + (n-1)(-6)


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Which value of x makes the equation 0.5(x + 15) = 2 + 0.75(x - 4) true?
SIZIF [17.4K]

Answer:

Step-by-step explanation:

\frac{1}{2}(x+15) = 2 + \frac{3}{4}(x-4)

To make this easier, to get ride of the fractions, we can multiply both sides by 4

2(x+15) = 8 + 3(x-4)

now use the distributive property

2x + 30 = 8 + 3x - 12\\

now we want to isolate x to one side and isolate all the constants to the other

2x - 3x = 8 - 12 - 30\\

now simplify

-x = -34\\x = 34

to test, we can plug in back to the original

\frac{1}{2}(34+15) = \frac{49}{2}\\\frac{8}{4} + \frac{3}{4}(34-4) = \frac{8}{4} + \frac{90}{4} = \frac{98}{4} = \frac{49}{2}

it works

7 0
3 years ago
What is 9/32 + 7/8 plz help
Furkat [3]

Answer:

1 5/32

Step-by-step explanation:

First, find common denominators. What you do to the denominator, you must do to the numerator.

First, multiply 4 to both the numerator and denominator of the second fraction:

(7/8)(4/4) = (7 * 4)/(8 * 4) = 28/32

Next, add across:

9/32 + 28/32 = 37/32

Simplify. Turn the improper fraction into a mixed fraction:

37/32 = (32 + 5)/32 = 1 5/32

1 5/32 is your answer.

~

4 0
3 years ago
Read 2 more answers
I need help on this please n-5>-2
Fofino [41]

Answer:

I think that it is n<3

Step-by-step explanation:

5 0
3 years ago
Write 9.74 ×104 in standard notation
IRISSAK [1]
The answer is <span>012.96. Hope this helps!


</span>
4 0
3 years ago
Find the definite integral from 0 to 1/16 of arcsin(8x)/sqrt(1-64x^2)dx
kolezko [41]
\displaystyle\int_0^{1/16}\frac{\arcsin8x}{\sqrt{1-64x^2}}\,\mathrm dx

First let y=8x, so that \mathrm dx=\dfrac{\mathrm dy}8 to write the integral as

\displaystyle\frac18\int_0^{1/2}\frac{\arcsin y}{\sqrt{1-y^2}}\,\mathrm dy

Now recall that (\arcsin y)'=\dfrac1{\sqrt{1-y^2}}, so substituting z=\arcsin y should do the trick. The integral then becomes

\displaystyle\frac18\int_0^{\pi/6}z\,\mathrm dz=\frac1{16}z^2\bigg|_{z=0}^{z=\pi/6}=\frac{\pi^2}{576}
8 0
3 years ago
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