Your answer would be the bottom right image. In the bottom right image, x is divided by 5 consistently. No function can be determined in the other tables.
If it says 3×8 its like saying 8+8+8=21.
It's just a faster way of adding.
Anything multiplied by 0 is 0.
Anything multiplied by 10 just add a 0 to the end of the number example 10×2=20.
Answer:
Either y =
or, y =
Step-by-step explanation:
We have to solve the following quadratic equation
45y² + 15y - 10 =0
Now, dividing both sides with 5 we get, 9y² + 3y -2 =0
Hence, to solve the above equation we have to factorize the left-hand part of the equation.
So, 9y² + 3y - 2 =0
⇒ 9y² +6y -3y -2 =0
⇒ (3y +2) (3y -1 ) =0
⇒ Either (3y +2) =0 or (3y -1) =0
⇒ Either y =
or, y =
(Answer)
Answer:
100%
Step-by-step explanation:
Probability of a product showing up in warehouse A =60%
Probability of a product showing up in warehouse B = 80%
Probability of 2 product showing up in warehouse A is
Probability of 1 product showing up in A and probability of 1 product showing up in A
A n A = 60% x 60% = 0.6 x 0.6 = 0.36 =36%
Probability of 2 product showing up in warehouse B is
Same as above
Probability of 1 product showing up in B and probability of 1 product showing up in B
B n B = 80% x 80% = 0.8 x 0.8 = 0.64= 64%
Probability of 2 product showing up in same warehouse is define as
Probability of 1 product showing up in A and probability of 1 product showing up in A or
Probability of 1 product showing up in B and probability of 1 product showing up in B
(AnA) U (BnB) =
36% + 64% = 0.36 + 0.64= 1
100%
Answer:
Contradiction
Step-by-step explanation:
Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.