I'm not sure what you mean, but if you mean 15 and 1/20th, you just multiply 15 by 20 and add one which is 301 and keep the denominator
Answer:
8 + 32v
Step-by-step explanation:
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s
In the given problem there are several known and important facts to take note of. Firstly the restaurant bill without tax and tips is $28.35. Then the tax of 6.25% needs to be added with the bill. Also a tip of 20% on the original bill needs to be added to find the total cost.
Then tax on the restaurant bill = (6.25/100) * 28.35
= 1.77
So the tax on the restaurant bill is $1.77
Amount of tips given = 28.35 * (20/100)
= 5.67
Amount of tips paid is $5.67
Total cost paid in the restaurant = ( 28.35 + 1.77 + 5.67) dollars
= 35.79 dollars