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kupik [55]
3 years ago
10

What is the solution to the system of linear equations?

Mathematics
1 answer:
GalinKa [24]3 years ago
4 0

Answer:

(0,2)

Step-by-step explanation:

The solution would just be where these two functions cross, which is at the point (0,2) in this case.

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son4ous [18]

Answer:

Step-by-step explanation:

4 0
3 years ago
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Simplify the expression completely. 7b+3(4b−2)+6÷3
Karo-lina-s [1.5K]

Answer:

19b-4

Step-by-step explanation:

7b+3(4b-2)+6÷3

Bracket comes first so we distribute 3 over the terms in the bracket

= 7b + 12b -6 +6 ÷ 3

First we solve division

= 7b + 12b -6 +6 ÷ 3

= 7b + 12b -6 +2

= (7b+12b)+(-6+2)

= 19b -4

This can't be simplified further as it can't be solved anymore

4 0
3 years ago
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Maria used a number line to find 12 ÷ 4.
aleksandrvk [35]

Answer:

12 divided by 4 is 3, this is how::

Step-by-step explanation:

            ------ .(-4)------- .(-4) ---------.(-4)

<---------------------------------------------------->

0  1  2  3  4  5  6  7  8  9  10  11  12

hope this made sense

8 0
3 years ago
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Is perpendicular to ? Explain.
olga2289 [7]
Two lines are perpendicular if and only if the product of their slopes is - 1.

So, you just need to find the slope of each line and find out the product of their slopes.

I will do one example for you.

L1: y = 3x + 5

L2: y = - 3x + 14

L3: y = -x/3 + 14

The slope of a line is the coefficient of the x.

So the slopes are:

L1: slope 3
L2: slope -3
L3: slope -1/3

So now multiply the slopes of each pair of lines:

L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular

L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular

L1 and L3: (3) *  (-1/3) = -1 => Yes, they are penpendicular.
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3 years ago
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Find the area of the figure.
Sveta_85 [38]

Answer: want it be add up all the sides and divide by 4\

Step-by-step explanation:

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3 years ago
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