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katrin2010 [14]
4 years ago
5

Find the sum of 136 +212. expkain why u did r did not regroup

Mathematics
2 answers:
mario62 [17]4 years ago
6 0
Line up 136 and 212 with 136 on top and 212 on the bottom.

  136
+212
____

now add up the end numbers, 6 and 2. That's 8. Since 8 is only a single-digit number, it fits in the space. Write that down under 6 and 2. 
Next, add up the middle numbers, 3 and 1. That's 4, it fits in the space, so you don't need to regroup here either. 
Now add up the first number in each, and that adds up to 3. 

The sum is the number you wrote down! It should look something like this.

  136
+212
____
348

You can say that the sum of these numbers is 348, and you did not have to regroup because the sums of each digit was under 10!
Arturiano [62]4 years ago
5 0
Each digit was under 10
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What is the range of possible sizes for side x
Xelga [282]

Answer:

0.5 < x < 16.5

Step-by-step explanation:

For a triangle (by the triangular inequality theorem), we know that the sum of any two sides must be larger than the other side.

When we have a triangle and we know two sides, let's define the measures of these sides as S1 and S2.   (such that S2 > S1)

By the first property, we will have that S1 + S2 > S3

Where S3 is the third side, the one that we do not know.

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This is because we also must have:

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We can rewrite both of these to get:

S2 - S1 < S3

S1 - S2 < S3

Because S2 > S1, the first inequality is more restrictive, so we need to use that one.

Then we get the inequality:

S2 - S1 < S3 < S1 + S2

Ok, in this case, the shorter side is 8.0 then:

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S2 = 8.5

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Replacing those in our inequality, we get:

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This is the range of possible sizes for side x.

3 0
3 years ago
What is the surface area
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A 1759 sq. units

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