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AlladinOne [14]
3 years ago
11

Which statement is valid when a circumscribed circle of an acute triangle is

Mathematics
1 answer:
Anni [7]3 years ago
4 0
<h3>There are two answers: Choice C, Choice D</h3>

Explanation:

For any acute triangle, the center of the circle is always inside the triangle.

For any right triangle, the center of the circle is the midpoint of the hypotenuse. The hypotenuse is the diameter of the circle.

For any obtuse triangle, the center of the circle is outside the triangle.

----------

Let's look at the answer choices more closely

A. False. This is only true if we have a right triangle as mentioned earlier.

B. False. This describes an inscribed circle.

C. True. As stated earlier.

D. True. This is based on how the circumscribed triangle is defined. It is set up to be the circle that goes through all three vertex points of a triangle. In other words, it is the smallest circle to completely enclose the given triangle.

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Pls help meh
LekaFEV [45]

Answer:

A≈254.47ft²

Step-by-step explanation:

A=πr2=π·92≈254.469ft²

7 0
3 years ago
5y + 3 &gt; −7y + 13 Multi-step linear inequalities
Artemon [7]

Answer:

y > \frac{5}{6}

Step-by-step explanation:

Given

5y + 3 > - 7y + 13 ( add 7y to both sides )

12y + 3 > 13 ( subtract 3 from both sides )

12y > 10 ( divide both sides by 12 )

y > \frac{10}{12} , that is

y > \frac{5}{6}

3 0
3 years ago
Please help me with this please and thank you
rjkz [21]

Answer:

Alright so the answer is B but I'll explain why because im nice ig.

Step-by-step explanation:

So lets do some calcumalations.

We'll use 1 as n and should get an output of 3 to check these formulas. Since 1 is the first term and 3 is the first term value makes sense alright.

So 9^1-1 is 0 and any number to the 0 power is 1 so that wont work.

3(4)^1-1 = 3(1); that's the answer

4^1-1 = 1, + 3 = 4 so that wont work either

I hope this helps ya have a great afternoon

8 0
2 years ago
Combine the like terms to create an equivalent expression: −4p+(−6p)
Step2247 [10]

Answer:

the answer is -10p

5 0
3 years ago
20 Points- Which of the following is true for f of x equals the quotient of the quantity x squared plus 9 and the quantity x min
tangare [24]

Answer:

There is a non-removable discontinuity at x = 3

Step-by-step explanation:

We are  given that

f(x)=\frac{x^2+9}{x-3}

We have to find true statement about given function.

\lim_{x\rightarrow 3}f(x)=\lim_{x\rightarrow 3}\frac{x^2+9}{x-3}

=\infty

It is not removable discontinuity.

x-3=0

x=3

The function f(x) is not define at x=3. Therefore, the function f(x) is continuous for all real numbers except x=3.

Therefore, x=3 is non- removable discontinuity of function f(x).

Hence, option B is correct.

5 0
3 years ago
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