This is a binomial probability situation, since a dog either is adopted or is not adopted. The chances of a dog's being adopted in 0.20. Here we're speaking of 9 visits. Thus, n=9, p=0.20.
One way of doing this problem is to calculate the probability that ONE dog will be adopted, and then that that TWO dogs will be adopted, and so on, up to NINE dogs. Add together these nine probabilities to get your answer.
But a better (faster) approach would be to calculate the probability that ZERO dogs will be adopted, and then to subtract this from 1.000.
Using my TI-84Plus calculator, I figured that P(0 dogs will be adopted) is binompdf(9,0.20,0), or 0.134. Subtracting this from 1.000, we get 0.866 (answer to this problem).
Answer:
here’s something that will help
answer is at the bottom if needed
Step-by-step explanation:
Answer:
It means that you need to state whether there are any solutions and how many there are. For example if the equation ends up with an answer like 2=5 there is no solution because 2 does not equal 5. if the equation ends up with an answer of 0=0 there is infinitely many solutions because 0 does equal 0. if it comes out as x=9 there is one solution because x only has one answer to (keep in mind these are just examples)
Step-by-step explanation:
The order pair would be where the two lines intersect perpendicularly with each other forming a 90° angle
Answer:
\left(\frac{\sqrt{78}}{30},\ \frac{\sqrt{78}}{39}\ ,\frac{41\sqrt{78}}{390}\right)
