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cestrela7 [59]
3 years ago
6

HELP ASAP PLEASE GIVING BRAINLIEST!!

Mathematics
1 answer:
Sholpan [36]3 years ago
3 0

Answer:

$0.51 = 0.51 in decimal form

Step-by-step explanation:

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What is an equation of the line that passes through the points ( 0,-7) and ( 5, -1)
tresset_1 [31]

Answer:

y = 5/6x - 5.167

Or

y = 5/6x - 31/6

Step-by-step explanation:

The equation of a line

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given points

( 0 , -7) ( 5 , -1)

x1 = 0

y1 = -7

x2 = 5

y2 = -1

Insert the values into the equation

m = -1 - (-7) / 5 - 0

m = -1 + 7 / 5

m = 6/5

y = 6/5x + c

Step 2: sub any of the two points given into the equation

y = 5/6x + c

( 5 , -1)

x = 5

y = -1

-1 = 5/6(5) + c

-1 = 5*5/6 + c

-1 = 25/6 + c.

c = -1 - 25/6

LCM = 6

c = -6 - 25 / 6

c = -31/6

c = -5.167

Step 3: sub c into the equation

y = 5/6x + c

y = 5/6x - 31/6

Or

y = 5/6x - 5.167

The equation of the line is

y = 5/6x - 5.167

7 0
3 years ago
Arlo invested $4000 in an account that earns 5.5% interest, compounded annually. The formula for compound interest is A(t)=P(1+i
USPshnik [31]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$4000\\ r=rate\to 5.5\%\to \frac{5.5}{100}\dotfill &0.055\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases} \\\\\\ A=4000\left(1+\frac{0.055}{1}\right)^{1\cdot 4}\implies A=4000(1.055)^4\implies A\approx 4955.2986

4 0
3 years ago
Read 2 more answers
Imagine being so epic that youd help me solve this
Aleksandr [31]

Answer:

B

Step-by-step explanation:

the graph will shift right about the x-axis

right mean that we will minus from x

so it will be B

hope this helps  

8 0
3 years ago
Please help!! Is it possible to prove that the triangles are congruent by using the AAS Congruence Theorem?
goldenfox [79]

Answer:

no, there is not enough information to use AAS congruence theorem to prove the triangles are congruent

6 0
3 years ago
A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the larger number a
mariarad [96]

Answer:

The two equations are

y = x - 3 and

3y = x + 9

Step-by-step explanation:

The options are not well stated. I'll answer the question without the options but however, my answer will be a reflection of one of the given options.

Given:

2 statements

Required

Write equivalent of both statements as equations

Let the large number be represented by x.

From the first statement (y, is equal to the difference of a larger number and 3)

Difference means minus (-); so, this statement is represented as follows to give us the first equation:

y = x - 3

From the second statement (The same number is one-third of the sum of the larger number and 9).

This is also represented as follows to give us the second equation

y = ⅓(x + 9)

Multiply both sides by 3

3 * y = 3 * ⅓(x + 9)

3y = x + 9

So, the two equations are

y = x - 3 and

3y = x + 9

4 0
3 years ago
Read 2 more answers
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