A taxi cab charges a pickup fee of $5.00and $2.50 for

Mathematics

1 answer:

Roman55 [17]4 years ago

7 0

I can’t see the whole question, but I’m guessing that the 2,50$ is for every km of minutes or whatever.

So I would answer A 2.50x + 5 because you have to pay 5$ for sure and the rest depends on the value of x to know how much more you’re going to pay!

I hope this helped, if there’s anything just let me know! ☻

You might be interested in

Lana wants to have $100,000 in 20 years. She plans to invest $8,000 to start and make yearly payments of $1,500 to the account.

kherson [118]

Answer:

Yes Lana will reach her goal she'll have 10,414.58 by the end of the 6 years,

Step-by-step explanation:

4 0

2 years ago

This is LCM and GCF I think

Ugo [173]

Yes it is LCM and GCF because you are trying to a factor that they both have

3 0

3 years ago

Read 2 more answers

I’ll give brainiest and 63 points to whoever helps me with 5-14<br> Find the slope of each line

stepan [7]

Answer:

Sorry that is toooooooooooooooooooooo much

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1) How do you find the sum of the exterior angle measures of any convex polygon?

skelet666 [1.2K]

Answer:

1) sum of all convex polygons' EXTERIOR ANGLES IS ALWAYS 360 DEGREES. If it is a triangle or even if it is a 25- gon.

2) if the polygon is regular then this means all of the sides are equal and all of the angles are equal to each other.

for example: Find the measure of an exterior angle of a REGULAR HEXAGON. so a regular hexagon has 6 sides all the same length and 6 exterior angles all the same measures. so to find the measure of 1 exterior angle you do 360 degrees /6 = 60 degrees. so an exterior angle of a regular hexagon is 60 degrees.

8 0

2 years ago

Need some help please.

melomori [17]

Applying the rules of exponents, the letter answers that form the code are: MATH IS NOT JUST ANOTHER FOUR LETTER WORD.

<h3>What are the Rules of Exponents?</h3>

Some of the rules of exponents to be applied are as follows:

$x^0 = 1\\\\x^m \times x^n = x^{(m + n)}\\\\x^{-m} = \frac{1}{x^m} \\\\x^m \div x^n = x^{(m - n)}\\\\$