Answer:
100 lightbulbs
Step-by-step explanation:
Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)
Hope this helps!
5 + 6a + 11b
terms: 5; 6a; 11b
Factors of 5: 1; 5
Factors of 6a: 1; 2; 3; 6; a; 2a; 3a; 6a
Factors of 11b: 1; 11; b; 11b
Answer:
x
8
−
256
Rewrite
x
8
as
(
x
4
)
2
.
(
x
4
)
2
−
256
Rewrite
256
as
16
2
.
(
x
4
)
2
−
16
2
Since both terms are perfect squares, factor using the difference of squares formula,
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
where
a
=
x
4
and
b
=
16
.
(
x
4
+
16
)
(
x
4
−
16
)
Simplify.
Tap for more steps...
(
x
4
+
16
)
(
x
2
+
4
)
(
x
+
2
)
(
x
−
2
)
Step-by-step explanation:
I would say 6 bc it’s a die of 6 and u get it 6 times