So,
We are trying to figure out when Grandpa Lopez's age was twice that of Dad.
Let x represent the number of years before/after when G. Lopez's age was twice that of Dad.
66 + x = 2(37 + x)
Distribute.
66 + x = 74 + 2x
Subtract x from both sides.
66 = 74 + x
Subtract 74 from both sides.
-8 = x
So 8 years ago, G. Lopez was twice as old as Dad. Let's check that.
66 - 8 = 58
37 = 8 = 29
29 * 2 = 58
58 = 58
It checks.
Answer:
Step-by-step explanation:
Let the number of jars is x.
<u>80 liters distributed, each jar has:</u>
<u>Redistribution with 4 less jars, each jar now has:</u>
<u>Each jar has now twice the amount:</u>
- 80/x*2 = 80/(x - 4)
- 2/x = 1/(x - 4)
- 2(x - 4) = x
- 2x - 8 = x
- x = 8
She prepared 8 jars at the start
I think it is the 3rd one but I might be wrong...
Only the third one makes x=-1 true
