(6x+9y=78) - (6x+4y=38) = (5y=40) = y=8
(2x+3(8)=26) = (2x+24=26) = (2x=2) = x=2
Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
This can either be done by multiplying with 125% (1.25) or, by dividing by dividing on 4 and adding a part.
This is the easiest way, tho.
60*1.25=75
The correct answer is 75 mph.
You can use the ASA postulate which means angle side angle. if 2 angles and the including side are congruent to the corresponding parts of another triangle then the triangles are congruent. hope that helps :)
Answer: 8/8
Step-by-step explanation:
