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2 years ago

What are the proofs

Mathematics

1 answer:

guajiro [1.7K]2 years ago

6 0

; 112 jumps ; 128 jumps ; 151 jumps ; 172 jumps

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In order to keep the rabbits out of the lettuce, Sue is going to put chicken wire around her garden. The diameter of the garden

ANTONII [103]

To keep rabbits away from lettuce garden, she need to set up chicken wire along the garden's circumference. If circumference comes out to be > 20 feet, then yes she will have enough chicken wire to surround the garden. If not , it will be food fest for rabbits. LoL!
Anyways,
Circumference of lettuce garden = pi x diameter of garden

= 3.14 x 6 = 18.84 feet.
Whereas, she has 20 feet of chicken wire.
So she will be left with 1-2 feet of wire.
Better luck for the next time Mr. Bunny :D

8 0

3 years ago

Find the equation in slope-intercept form of a line through (2, 4) with slope 0. Oy=2 Ox=2 Oy=4 0 x = 4

alexdok [17]

X=5 because that’s the slope of the question

6 0

3 years ago

A rectangle has a length (2x−5) and a width of (x−3) . What is the area of the rectangle?

mrs_skeptik [129]

Answer:

2x² - 11x + 15

Step-by-step explanation:

Find the area of the rectangle by multiplying the length and width together, using FOIL

(2x - 5)(x - 3)

Multiply the first terms:

(2x)(x) = 2x²

Multiply the first term in the parentheses by the last term in the second set of parentheses:

(2x)(-3) = -6x

Multiply the second term in the first set of parentheses by the first term in the second set:

(-5)(x) = -5x

Multiply the last terms:

(-5)(-3) = 15

Add these all together, then add like terms

2x² - 6x - 5x + 15

2x² - 11x + 15

So, the area of the rectangle is 2x² - 11x + 15

4 0

2 years ago

You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.

RUDIKE [14]

Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

P = x + 2y

The area of the rectangle is given by xy,

i.e.

$xy = 288 \\ \\ \\ \\ \Rightarrow y= \frac{288}{x}$

Substituting for y into the equation for the length of fencing needed, we have

$P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}$

For the amount of fencing to be minimum, then

$\frac{dP}{dx} =0 \\ \\ \Rightarrow1- \frac{576}{x^2} =0 \\ \\ \Rightarrow \frac{576}{x^2} =1 \\ \\ \Rightarrow x^2=576 \\ \\ \Rightarrow x=\sqrt{576}=24$

Now, recall that

$y= \frac{288}{x} = \frac{288}{24} =12$

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

Therefore, 48 feets of fencing is needed to enclose the garden.

8 0

3 years ago

What is 4,000,000 + 700,000 + 20,000 + 9,000 + 600 + 60 + 2 in standard form?

Ivanshal [37]

Answer:

4729662

Step-by-step explanation:

5 0

2 years ago