Answer:
B) f(g(x)) = 15x² + 18
Step-by-step explanation:
Plug the entire equation of g(x) in for the x in f(x)
f(g(x)) = 5(3x² + 3) + 3
f(g(x)) = 15x² + 15 + 3
f(g(x)) = 15x² + 18
Answer: D
Step-by-step explanation:
because 320/4 = 80 mi/hr because it can not km or min and hr^2 would not make any sense
In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.
Let's start with the first equation.
Cross multiply both sides of the equation.
Subtract 6x on both sides of the equation.
Divide both sides of the equation by -5.
Therefore, the slope of the first equation is 4/5.
Let's now simplify the second equation.
Add x on both sides of the equation.
Divide both sides of the equation by -4.
Therefore, the slope of the second equation is -5/4.
Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.
Answer:
Yes
Step-by-step explanation:
You can get there a couple of ways. One makes use of the secant rules that tell you ...
PQ × PR = PS × PT
Substituting for PR and PT, you have ...
PQ × (PQ + QR) = PS × (PS + ST)
PQ² + PQ×QR = PS² + PS×ST
Substituting PQ for PS everywhere, we have ...
PQ² + PQ×QR = PQ² + PQ×ST
Dividing by PQ gives ...
PQ + QR = PQ + ST
and subtracting PQ leads us to the conclusion ...
QR = ST
_____
Another way to look at it is to draw the chord QS. Then ΔQPS is an isosceles triangle, and the perpendicular bisector of QS bisects ∠P and also goes through the circle center. Then the figure is symmetrical about that diameter secant, making QR ≅ ST.
