The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
4×2=8. 100×2=200
8% out of 200
so
4=8 if you have double, 200
Answer:
x = 27
Step-by-step explanation:
Both angles together form 180 degree.
Set your formula up as
180 = (5x+2) + (x + 16)
180 = 5x + 2 + x + 16
180 = 6x + 18
180 - 18 = 6x
162 = 6x
162/6 = x
27 = x
treat the tree trunk as a cylinder
v= pi x r^2 x h
using 3.14 for pi
3.14 x 3^2 x 10 = 282.6 cubic feet
282.6 * 45 = 12, 717 pounds
