(5 + 6)3 would represent what you want.
Answer:
center of circle: (0,6)
radius: 4
the point (sqrt17,7) is NOT located on this circle. It is outside of the circle. This circle cuts off at (sqrt15,7), therefor (sqrt17,7) is not included
So, since there are two equations, we can substitute one of them into the other. In this case, it would be easiest to substitute 2b=6a-14 into the other equations. But first, simplify by dividing both sides by 2. You bet b=3a-1
We can now plug this into the other equation
Sine the equation b=3a-1 results in the value of b, we have to plug in for the value of b in the other equation
So this is what we get after plugging in:
3a-(3a-1)=7
Now, simplify. 3a-3a+1=7
Since 3a-3a = 0, this equation results in a no solution
Answer:
The result is a no-solution, or Ф
Hope this helped!! :D
Y = 4x - 3
y = 1/3x + 4
y = -4/5x + 5
y = 3x + 10
