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Artemon [7]
3 years ago
13

How do you subtract 7 2/8 - 6 10/16

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0

Answer:

you would first make them improper fractions

58/8 - 106/16

then you would time 58/8 by 2/2 to get like denominators

116/16 - 106/16= 10/16= 5/8

So your answer is 5/8

Step-by-step explanation:

Nutka1998 [239]3 years ago
6 0

Answer:

1 3/5

Step-by-step explanation:

you have to make 7 2/8 into a common denominator which will be 16

1. 7 2/8 = 7 4/16

2. subtract 6 10/18 and 7 4/10

3 you get 1 6 /10 but u simplify it to 1 3/5

4 your final answer is: 1 3 /5

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8 0
3 years ago
A circle cuts the x-axis at (4,0) and (14,0), and cuts the y-axis at (0,6) and (0,8). Find it's equation
gayaneshka [121]
It is not a circle but you can find the equation of the ellipse.
To do this we need to work out the major and minor radii and the centre
The centre is at (9, 7)
The major (y) radius is 1 and the minor (x) radius is 5
Therefore the equation is (x-9)/5 + (y-7)/1 = 1
5 0
3 years ago
7.7.33
GenaCL600 [577]
We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%

</span>i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals


the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
7 0
3 years ago
The solution of |x-2|&gt;5
zzz [600]

Answer:

Step-by-step explanation:

|x-2|>5

x-2<-5

x<-3

or x-2>5

x>7

5 0
3 years ago
Read 2 more answers
Determine whether the function ƒ(x) = x4(x2 − 1) is even, odd or neither.
Scrat [10]
F(x) = x4(x2 - 1)
f(-x) = (-x)4((-x)2 - 1)
f(-x) = x4(x2 - 1)
from above explanation it is clear that the function is even.
7 0
3 years ago
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