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inessss [21]
3 years ago
6

Question about trig ratios

Mathematics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

Cos a

=opposite/hypotenuse=9/3√13

=3/√13=3√13/13

Sin a

=Adjacent/hyp=6/3√13

=2/√13=2√13/13

Tan a=opposite/adjacent=9/6

=3/2

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