Answer:
7 ft 1 1/4 in
Step-by-step explanation:
The total width of 3 paintings and 2 spaces is ...
(10.5 in) + (3 in) + (3 ft 6 in) + (3 in) + (2 ft 2 3/4 in)
= (10.5 +3 +6 +3 +2.75) in + (3 +2) ft
= 25.25 in + 5 ft = 1.25 in + 24 in + 5 ft
= 7 ft 1 1/4 in
The total width of wall space needed for the paintings is 7 feet 1 1/4 inches.
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If two more 3-inch spaces are added, one on each end, then the total width is 7 feet 7 1/4 inches. The problem isn't clear about that, saying only that there are spaces between the paintings.
<h2>
Answer:</h2>
The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:
Origin.
<h2>
Step-by-step explanation:</h2>
A function f(x) is said to be a odd function if:

Also, an odd function always has a symmetry with respect to the origin.
whereas a function f(x) is said to be a even function if:

Also, an even function has a symmetry with respect to the y-axis.
We know that:
Tangent function, cotangent function and cosecant function are odd functions.
Since,

( similarly sine function is also an odd function.
whereas cosine and secant function are even functions )
<em>Hence, the graph of tangent function, cotangent function and cosecant function is symmetric about the origin.</em>
Answer: 171
Step-by-step explanation:
An obtuse angle means more than 90 degrees. (90 degrees would be the inside corner of your notebook paper) a straight line would be 180 degrees. 171 is the closest to 180
Solution: f(18.5)=31.47
Step by step solution:
I started by making an equation in slope intercept form- I found the slope, 28/17, with the points (4, 17) and (12.5, 31). Then I found the y intercept, 1, with the point (4, 17). So the equation is y=28/17x+1. Then I just plugged 18.5 where the x is and solved for y
28/17(18.5)+1=y
28/17(37/2)+1=y
1036/34+1= y
30.47+1=y
y=31.47
Keep in mind that 1036/34 is not exactly 30.47 but that 30.47 was rounded to the nearest hundredth
Hope this helps :)
I'm going to have to go with choice "c". 10x - 1 with the remainder of 5