3 years ago

Find the area of 3/4 of the circle (radius = 6) i need the awncer please

Mathematics

2 answers:

IceJOKER [234]3 years ago

6 0

28.6 good luck that’s the answer

kobusy [5.1K]3 years ago

3 0

Answer:

28.26

Step-by-step explanation:

I hope this helps!

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find the approximate area of the shaded region below, consisting of a right triangle with a circle cut out of it. Use 3.14 as an

skad [1K]

Answer:

2794 m^2

Step-by-step explanation:

Area of Triangle - Area of Circle

1/2bh - piR^2

4050 - 1256

= 2794

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3 years ago

Which is the solution to the equation solved for p? (q + p)q = (s + r)s

Brums [2.3K]

Answer:

Option B

Step-by-step explanation:

$(q + p)q = (s + r)s$

Lets open the brackets of L.H.S.

$=> q^2 + pq = (s+ r)s$

Lets substract q² from both the sides.

$=> q^2 + pq - q^2 = (s + r)s - q^2$

$=> pq = (s + r)s - q^2$

Lets divide both the sides by q.

$=> \frac{pq}{q} = \frac{(s + r)s - q^2}{q}$

$=> p = \frac{(s + r)s }{q} - \frac{q^2}{q} = \frac{(s + r)s}{q} - q$

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3 years ago

Determine if the given differential equation is exact (e^2y-y cos xy)dx+(2xe^2 y-cos xy+2y)dy=0

rewona [7]

$\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy$

$\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy$

The partial derivatives are not equal, so the equation is not exact.

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3 years ago

Helen earns $12 each weekend by babysitting her brother.After the third weekend,Helen buys a new cd for $12.48.How much money do

GalinKa [24]

She would have $23.52 because 12 times 3 is 36 and 36-12.48=23.52

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3 years ago

Read 2 more answers

Given the line below. Write the point-slope form of the given line that passes through the points (0, 3) and (4, 0). Identify (x

jeka57 [31]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 0}} &,&{{ 3}}~) 
% (c,d)
&&(~{{4}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{0-3}{4-0}\implies -\cfrac{3}{4}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-3=-\cfrac{3}{4}(x-0)$

4 0

3 years ago